A parallel plate capacitor of capacitance 2 F is charged to a potential V. The energy stored in the capacitor is E 1 . The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is E 2 . The ratio 
is
Text Solution
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The charge on the plates of the first capacitor when connected against the potential difference V is given by Q=CV
=2V
When both the capacitors are connected, from the conservation of charge, it can be written that
2V = 2V' + 1V'
where, V is the new potential difference across each capacitor.
The formula to calculate the energy stored in the first capacitor is given by
...
For the second case, the energy stored in the combination of capacitor is given by
…
Divide equation by equation to obtain the required ratio of the stored energy.
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